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Sayali Bagwe •

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... B= 2 kHz and (S/N) = 24dB
$∴24=10 \log_10 \big(\frac{S}{N}\big) \\
∴\frac{S}{N}=251$
**Channel capacity:**
$C= B \log_2 \big[1+\frac{S}{N}\big] \\
=2 \times 10^3 \log_2[1+251] \\
C = 15.95 \times 10^3 bits/sec$
**B is halved:**
$∴ b.w, B_2=1kHz, old b.w., B_1=2 kHz \\
∴N=N_o B,∴N ...

written 5 months ago by
Sayali Bagwe •

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... 1. Calculate max capacity of this channel.
2. Assuming constant transmitting power, calculate max. capacity when channel b.w is 1 halved 2, reduced to quarter of its original value.
**Subject**: Computer Engineering
**Topic**: Electronic Circuits and Communication Fundamentals
**Difficulty**: Me ...

written 5 months ago by
Sayali Bagwe •

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... Given: Bit rate (n) = 8000 bps
Band rate = 1000 band
To find:
1. Data elements carried by each signal element (R)
2. Total signal element (L)
R=?
Bit rate = numbers of data elements per (R) signal × band rate
∴$R=\frac{\text{bit rate(n)}}{\text{Band rate}} =\frac{8000}{1000}=8 Bit/ ...

written 5 months ago by
Sayali Bagwe •

**2.0k**0

votes

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answer

227

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... **Subject**: Computer Engineering
**Topic**: Electronic Circuits and Communication Fundamentals
**Difficulty**: Medium / High ...

written 5 months ago by
Sayali Bagwe •

**2.0k**0

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... Given: - B = 3100 Hz
$\big(\frac{S}{N}\big)dB=10$
$∴10=10 log_{10}big(\frac{S}{N}\big) \\
∴\frac{S}{N}=10$
∴ Maximum bit rate
$= R_{\max} = B \log_2 \big[1+\frac{S}{N}\big] \\
= 3100 \log_2(1+10) \\
=\frac{3100 \log_{10}11}{\log_{10}2} \\
= 10,724 bits/sec$
...

written 5 months ago by
Sayali Bagwe •

**2.0k**0

votes

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191

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... **Subject**: Computer Engineering
**Topic**: Electronic Circuits and Communication Fundamentals
**Difficulty**: Medium / High ...

written 5 months ago by
Sayali Bagwe •

**2.0k**0

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... Given B = 3100 Hz
S/N = 20 dB
But 20 dB = 10 log (S/N)
∴ S/N = 100
The maximum bit rate: -
$R_{\max }=B \log_2 \big[1+\frac{S}{N}\big] \\
=3100 log_2[1+100 ] \\
=\frac{(3100 \log_{10}101 )}{log_{10}2 } =20,640 bits/sec$
...

written 5 months ago by
Sayali Bagwe •

**2.0k**0

votes

1

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152

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... **Subject**: Computer Engineering
**Topic**: Electronic Circuits and Communication Fundamentals
**Difficulty**: Medium / High ...

written 5 months ago by
Sayali Bagwe •

**2.0k**0

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... **Channel capacity (C):**
The channel capacity is defined as the maximum data rate at which the digital date can be transmitted over the channel reliably.
The various concepts related to channel capacity are:
**Data Rate:**
It is defined as no. of bits transmitted by the transmitted per second ...

written 5 months ago by
Sayali Bagwe •

**2.0k**0

votes

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161

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written 5 months ago by
Sayali Bagwe •

**2.0k**