Mumbai University > FE > Sem 1 > Basic Electrical and Electronics Engineering

Marks: 8 M

Year: Dec 2013

Condition for maximum efficiency

We know that,

$Ƞ = output/ output + losses$

Considering the secondary side,

$Ƞ= V_2I_2\cosф2/ V_2I_2\cosф2 + W1 + I^2_2Ro2$

Diff w.r.t. I2,

For maximum efficiency, $dn/dI2 = 0$

$dn= (V_2I_2\cosф2/ V_2I_2\cosф2 + W1 + I22Ro2) Y2 \cos ф2 \\ dI= V_2I_2\cosф2/ V_2I_2\cosф2(V2 \cosф2 + W2Ro2/ …