A 50KVA, 4400/220 volt transformer has R1=3.45Ω, R2=0.009Ω. The reactance are X1=5.2Ω and X2=0.015Ω. Calculate for the transformer. - Full load current on primary and secondary side. - Equivalent resistance, reactance, impedances, referred to primary side and secondary side and Total Copper Loss using individual resistance and equivalent resistances. -

Given:

50 KVA

4400/220 volt transformer i.e.

E1=4400V

E2=220V

R1=3.45Ω

R2=0.009Ω

X1=52Ω

X2=0.015Ω

$K=\dfrac{E_2}{E_1} =0.05$

$I_1$ $=\dfrac{\text{KVA rating}\times1000}{E_2} \\ =\dfrac{50\times1000}{4400}\\=11.3636A$

$I_2$ $=\dfrac{\text{KVA rating}\times1000}{E_2} \\ =227.2727$

In reference to primary side

Resistance, R01=R1+R21

$R_{01}=R_1+\dfrac{R_2}{K^2}=3.45+\dfrac{0.009}{(0.05)^2}=7.05\Omega$

Reactance, X01=X1+X21

$X_{01}=X_1+\dfrac{X_2}{K^2}=5.2+\dfrac{0.015}{(0.05)^2}=11.2\Omega$

Impedance, $Z_{01}=\sqrt{R_{01}^2+X _{01}^2 } =13.23Ω$

In reference to secondary side,

Resistance,

$R_{02}$ $=R_2+R_1^1 \\ …