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Due to slipping, points A and B on the rim of the disc have the velocities $V_a = 1.5m/s$ to the right and $V_b = 3m/s$ to the left as shown in figure.

Determine the velocities of the centre point C and point D on the rim at this instant. Take radius of disc 0.24m.

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Instantaneous centre of rotation, I of the disk lie on line perpendicular to the velocities at point A and B.

Let $IA=x$

Radius $= 0.24m$ (Given)

$IB = 0.48 – x$

w- Angular velocity of the disk,

$w=\dfrac vr \\ \dfrac {V_A}{IA} = \dfrac {V_B}{IB} \\ \dfrac {1.5}x= \dfrac 3{0.48-x} …

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