$Q_(n-shields)$=$\frac{Aσ(T_1^4-T_2^4)}{((n+1)[\frac{2}{ϵ}-1])}$

Radiation heat transfer between two large parallel plates of emissivitiesε_1 and ε_2 maintained at uniform temperatures T1 and T2 is given by

Q_(12,no shield)=(Aσ(T_1^4-T_2^4))/(1/ε_1 +1/ε_2 -1)

Now consider a radiation shield placed between these two plates, as shown in Figure

Fig: The radiation shield placed between two parallel plates and …