Question Paper: Design of Machine Elements I : Question Paper Dec 2015 - Mechanical Engineering (Semester 5) | Pune University (PU)
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## Design of Machine Elements I - Dec 2015

### Mechanical Engg (Semester 5)

TOTAL MARKS: 100
TOTAL TIME: 3 HOURS
(1) Question 1 is compulsory.
(2) Attempt any four from the remaining questions.
(3) Assume data wherever required.
(4) Figures to the right indicate full marks.

### Solve any one question from Q1 and Q2

1 (a) Two rods are connected by means of a knuckle joint. The axial force 'P' acting on the rods is 25KN. The rods and the pin are made of plain carbon steel 45C8 (Syt = 380N/mm2) and factor of safety is 2.5. The yield strength in shear is 57.7% of the yield strength in tension.
Calculate
i) The dia. of rods.
ii) The diameter of the pin.
(6 marks)
1 (b) What is the effect of keyway cut into the shaft? How it can be Compensated?(4 marks) 10 (a) How will you find whether the given helical spring is a compression spring or tension spring.(4 marks) 10 (b) A load of 1KN dropped axially on a closed coiled helical compression spring from a height of 250 mm. The spring has 20 active coils. Take wire diameter as 20mm. Spring index is 8. Determine the deflection and stress induced in the spring. Take G = 0.84 × 105 Mpa.(12 marks) 2 (a) Fig(1) shows a hanger with rectangular c/s with the proportions indicated. The force p acting on the hanger is 6KN and acts at 30° to the vertical as shown. The permissible stress in the hanger material is 60 MPa. Determine the size of the cross section. (6 marks) 2 (b) (i) What is the purpose of rubber bush in bushed pin flexible coupling?(6 marks) 2 (b) (ii) What is the difference between splines and keys?(4 marks)

### Solve any one question from Q3 and Q4

3 (a) A shaft and key are made of the same material and the key width is 1/3rd of the shaft diameter.
i) considering shear only, determine the minimum length of key, in terms of the shaft diameter
ii) Determine thickness of the key, to make the key equally strong in shear and crushing, taking the shear strength of the key material as 40% of its crushing strength.
(8 marks)
3 (b) Prove that a square key is equally strong in shear and crushing.(2 marks) 4 (a) Differentiate between torsional rigidity design and lateral rigidity design of shafts.(4 marks) 4 (b) A 40 mm diameter shaft is made of steel 50 C4 (sut = 660 N/mm ) and has a machined surface. The expected reliability is 99%. The theoretical stress concentration factor for the shape of the shaft is 1.6 and the notch sensitivity factor is 0.9. Determine the endurance limit of the shaft ka=0.76, kb=0.85 kc=0.814.(6 marks)

### Solve any one question from Q5 and Q6

 Nominal diameter, mm 40 50 60 70 Core diameter, mm 32.5 41.5 50.5 39.5 Mean diameter, mm 36.5 46 55.5 65 Core area, cm2 8.3 13.53 20.03 27.81 pitch mm 7 8 9 10
(10 marks)

### Solve any one question from Q7 and Q8

7 (a) The pull in the tie rod of an iron truss is 50KN. Design a suitable adjustable steel screwed joint. The permissible stresses are 75MPa in tension, 45MPa in shear and 90 MPa in crushing.(8 marks) 7 (b) A bracket carrying a load of 15KN is to be welded as shown in fig(2) find the size of weld required if the allowable shear stress is not to exceed 80 N/mm2. (10 marks) 8 (a) A steel plate subjected to a force of 3KN and fixed to a vertical channel by means of four identical bolts as shown in fig(3) the bolts are made of plain carbon steel 45C8 (Syt = 380 N/m2) and the factor of safety is 2. Determine the diameter of the shank. (10 marks) 8 (b) (i) What are the advantages of welded joints compared with riveted joints?(4 marks) 8 (b) (ii) Discuss on bolts of uniform strength.(4 marks)

### Solve any one question from Q9 and Q10

9 (a) What is mean by spring surge and what is its effect.(4 marks) 9 (b) A helical spring whose mean diameter of the coils is 8 times that of wire, is to absorb 400 N.m of energy. The initial compression of the spring is 50mm and compress by additional 70mm while absorbing the shock. The maximum allowable stress is 400Mpa. and G = 84×103 GPa. Determine the diameter of wire, and the number of active turns Neglect the effect of stress concentration.(12 marks)