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Find the core radius necessary for single mode operation at 820nm of step index fiber with $n_1=1.482$ and $n_2=1.474$
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written 7.2 years ago by
teamques10
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Given: $ λ =820nm \\ n_1=1.482 \\ n_2=1.474 \\ V = 2.405 \text {(single mode step index)} $
To Find:
1) Core radius (a)
2) Numerical aperture (N.A)
3) acceptance angle (Өa)
4) solid angle (τ)
Solution:
$\Rightarrow N.A = \sqrt{n_1^2-n_2^2 } \\ =\sqrt{1.482^2-1.474^2 } \\ N.A= 0.153 $
Numerical …
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