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A grating has 10000 lines/cm & its total width is 5 cm. Calculate for $\lambda$ = 6000$\mathring{A}$ in the 2nd order its RP & the smallest difference in $\lambda$ which can be just resolved.
written 6.3 years ago by gravatar for neeta.vanage neeta.vanage • 850 modified 2.2 years ago by gravatar for pedsangini276 pedsangini276 • 4.7k

Subject: Applied Physics 2

Topic: Interference And Diffraction

Difficulty: Medium
engineering physics
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written 6.2 years ago by gravatar for neeta.vanage neeta.vanage • 850

N = 10000 lines/cm, Width W = 5 cm, λ = 6000 Å, n = 2, RP = ?, dλ = ?

Total number of lines on grating are N = 10000x 5 = 50000

RP = nN

RP = 2x 50000

RP = 100000

$\frac{λ}{dλ}$ = RP

100000 = $\frac{6000 \times 10^{-8}}{dλ}$

dλ = 0.06 A°
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