1
814views
Write short note on Minor losses in pipe.
1 Answer
1
2views

$$ \begin{aligned} &\frac{P_{\mathrm{o}}}{\gamma_{\mathrm{o}}}+\frac{V_{\mathrm{o}, \text { avg }}^{2}}{2 g}+z_{\mathrm{o}}=\frac{P_{\mathrm{i}}}{\gamma_{\mathrm{i}}}+\frac{V_{\mathrm{i}, \text { avg }}^{2}}{2 g}+z_{\mathrm{i}}-h_{\mathrm{L}}+h_{\mathrm{P}}-h_{\mathrm{T}} \ &h_{\mathrm{L}}=h_{\mathrm{L}, \text { major }}+h_{\mathrm{L} \text {, minor }} \end{aligned} $$ major losses: due to viscous effects in straight pipes minor losses: due to viscous effects in pipe components Note: "minor" does not mean $h_{\mathrm{L}, \text …

Create a free account to keep reading this post.

and 4 others joined a min ago.

Please log in to add an answer.