written 6.2 years ago by | • modified 2.2 years ago |
Subject : Applied Mathematics 2
Topic : Triple integration and Applications of Multiple integrals
Difficulty : Medium
written 6.2 years ago by | • modified 2.2 years ago |
Subject : Applied Mathematics 2
Topic : Triple integration and Applications of Multiple integrals
Difficulty : Medium
written 6.0 years ago by |
Transforming to spherical coordinate by putting $x = r \hspace{0.1cm}sin \theta cos \theta , y=r \hspace{0.1cm}sin \theta \hspace{0.1cm}sin \phi, z=r \hspace{0.1cm}cos \theta$ and $dx\hspace{0.1cm}dy\hspace{0.1cm}dz = r^2sin \theta \hspace{0.1cm}dr \hspace{0.1cm}d \theta \hspace{0.1cm}d \phi$
$I = \int^{\pi/2}_{\phi=0}\int^{\pi/2}_{\theta=0}\int^a_{r=0} r^5\hspace{0.1cm}sin^3 \theta\hspace{0.1cm}cos \theta \hspace{0.1cm}sin \phi\hspace{0.1cm} cos \phi \hspace{0.1cm} dr \hspace{0.1cm} d\theta \hspace{0.1cm} d\phi\\ \hspace{0.1cm}=\int_0^{\pi/2}sin \phi \hspace{0.1cm}cos \phi \hspace{0.1cm}d\phi \int_0^{\pi/2} sin \theta \hspace{0.1cm}cos \theta \hspace{0.1cm} d \theta \int_0^ar^5\hspace{0.1cm}dr\\ \hspace{0.1cm}=\big[\frac{sin^2\theta}{2}\big]_0^{\pi/2}\big[\frac{sin^4\theta}{4}\big]_0^{\pi/2}\big[\frac{r^6}{6}\big]_0^a\\ \hspace{0.1cm}=\frac{1}{2}.\frac{1}{4}.\frac{a^6}{6} = \frac{a^6}{48}$