Mechatronics - December 2016
MU Mechanical Engineering (Semester 6)
Total marks: --
Total time: -- INSTRUCTIONS
(1) Assume appropriate data and state your reasons
(2) Marks are given to the right of every question
(3) Draw neat diagrams wherever necessary 1(a) With block diagram explain a Mechatronics Design process. 5 marks
1(b) Explain Inertia matching with a sketch. 5 marks
1(c) Explain procedure for selection of actuator. 5 marks
1(d) Explain procedure for Cantilever beam vibration control using piezo sensors. 5 marks
1(e) Draw properly labeled sketch of a torque development process in three phase motor and explain. 5 marks
2(a) Explain heat dissipation in DC motor and Derive an equation for thermal modeling of DC motor. 5 marks
2(b) Explain Piezoelectric drives with neat sketch. State its applications. 5 marks
3(a) Two double acting pneumatic cylinders A, B are selected for an industrial application. The sequence of movement for cylinder is as indicated below-
(AB)+Delav (5sec) (AB)- Draw the electropneumatic circuit using 5/2 double solenoid as final directional control valves. 5 marks
3(b) Explain with diagram procedure for interfacing motor drive with microcomputer system. 5 marks
4(a) Explain Stepper motor performance charateristics with neat sketch. 5 marks
4(b) Explain with a block diagram Multichannel Data Acquisition systems (DAQs). State its benefits 5 marks
5(a) Write PLC ladder logic diagram as per the operational sequence given below figure.
!mage An explanation of the operational sequence is as follows:
Step1:The sequence begins by pressing the start button I: l in rung 0. As output 0.2/0 becomes energized, the rung becomes latched and corresponding contacts in rungs l. 3. 5. 6. and 9 close. The system becomes de-energized by pressing the stop button l: 1/0 in rung 0.
Step2:The closure of the start button also causes rung l to latch. By energizing output 0:2/l in rung 1. both conveyor belts begin running. When an empty can from the input conveyor enters the slot in position 1. it activates a limit switch that turns rung 2 True. As the output of rung 2 energizes, it Creates a False condition at Examine- Off contact 0:2/2, rung 1 unlatches, and the conveyor belts stop. Rung 3 is now in the True condition.
Step 3: When rung 3 becomes True. its output causes a valve to open and paint pours into an empty can at position 9. As the paint fills the can, a strain gauge measures the weight and sends a voltage, which is proportional to the weight of the paint, to an analog-to-digital module in the PLC The A/D converter module produces a proportional digital value at address 1:6.0. This digital value is compared using the EQU instruction on rung 4. Source A of the EQU instruction is the weight of the paint and source B is the program constant of 128.
Step4:When the paint can fills to I28 ounces, the values at source A and source B of the EQU instruction are the same. which energizes the rung and turns on B3/0 The corresponding Examine-Off (B3/0) on rung 3 becomes False and shuts off the valve. Also. the B3/0 contact on rung 6 energizes the rung. causing a robotic arm to place a lid on the can. When sensor 1: l/4 in rung 6 detects the placement of the lid. it causes the rung to latch, starting a motor that rotates the table.
Step5: As the table and incremental encoder rotate, the tip-counter C5:0 in rung 8 increments. Alter 72 pulses, the accumulator equals the preset value. The DN output of the counter then sets. causing the corresponding Examine-Off contact in rung 6 to become False. The result is that the rung unlatches and the rotary motor stops. 5 marks
5(b) Draw a block diagram representing Car range management system. 5 marks
Write a short note any four Q1.(a,b,c,d,e)6(a) Accumulator 5 marks
6(b) Selection of a PLC robot. 5 marks
6(c) Fire fighting robot. 5 marks
6(d) Comb drive 5 marks
6(e) Mechatronics systems in factory and business applications. 5 marks