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Analyse the contineous beam by using three moment theorem
written 5.7 years ago by | • modified 5.7 years ago |
Subject: Structural Analysis II
Topic: Flexibility Method
Difficulty: Medium / High
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written 5.7 years ago by | • modified 5.7 years ago |
Subject: Structural Analysis II
Topic: Flexibility Method
Difficulty: Medium / High
written 5.7 years ago by |
1)Free Bending moment
For Span BC at $F=\frac{wl^{2}}{8}=\frac{2\times(6)^{2}}{8}=9kN.m$
For Span CD at $G=\frac{wl^{2}}{8}=\frac{2\times(8)^{2}}{8}=16kN.m$
2) Free Bending moment diagram
3) Find Reaction at Support:-
Reaction at $B=4+4.94=8.94kN$
Reaction at $C=7.06+9.16=16.23kN$