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The following record refer to and operation involving reciprocal levelling.
Instrument at Staff reading on A Staff reading on B Remarks
A 1.155 2.595 Dist. AB = 500m RL of A = 525.500
B 0.985 2.415

Find=

1. the true RL of B

2. the combine correction for curvature and refraction

3. the collimation error

4. whether the line of collimation is included upward and downward.


1 Answer
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1. The true RL of B

The difference of level between A and B

=[(0.2955-1.155)+(2.415-0.985)] / 2

=1.435m (fall from A to B) …………………………………………………………………(1)

RL of B = 525.500-1.435= 524.065m

2. the combine correction for 500m curvature and refraction D = (0.0673DD) = (0.06730.50.5) = 0.0168m …

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