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The following bearing observed in the area where local attraction was suspected determine the correct magnetic bearing if the declination is 3$^\circ$30' east.
1 Answer
written 5.7 years ago by | modified 5.6 years ago by |
Line | FB | BB | Declination |
---|---|---|---|
PQ | 220$^\circ$30' | 41$^\circ$15' | 3$^\circ$30'E |
QR | 260$^\circ$45' | 79$^\circ$30' | 3$^\circ$30'E |
RS | 19$^\circ$30' | 200$^\circ$ | 3$^\circ$30'E |
SP | 100$^\circ$ | 280$^\circ$ | 3$^\circ$30'E |
The difference of BB and FB of SP is 180O hence station S and P free from local attraction
FB of PQ= 220$^\circ$30’, BB Of PQ= 41$^\circ$15’
FB-BB= 220$^\circ$30’ - …