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Given set of points use Hough transform to joint these points. $A (1,4), B (2,3), C (3,1), D (4,1), E (5,0)$
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written 5.7 years ago by
teamques10
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Line equation can be given as,
$y = ax +b$
which can be expressed as, $b = - ax + y$
| Points(x,y) | $b = - ax + y$ | Line slope points (a,b) |
|---|---|---|
| A (1,4) | $b = - a + 4$ | (4, 4) |
| B (2,3) | $b = - 2a + 3$ | (1.5, 3) |
| C (3,1) | $b = - 3a + 1$ | (0.33, 1) |
| D (4,1) | $b = - 4a + 1$ | (.25, 1) |
| E (5,0) | $b = - 5a$ | (0, 0) |
Plotting line slope points, refer Graph 1
From the graph, it is clear that a maximum pf three-line pass through point $(- 1, 5). i.e. a = - 1, b = 5$
Putting a and b values in line equation,
$$y = ax +b \\ y = - x + 5$$
i.e. x = 5 and y = 5
therefore, final plot can be plotted as,
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