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Given set of points use Hough transform to joint these points. A (3,4), B (0,-4), C (1,4), D (6,12), E (4,1), F(1.5, 0), G(-2, 2), H(-1,-3), I(3,-2)
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written 5.6 years ago by
teamques10
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Line equation can be given as, $$y = ax +b$$ which can be expressed as, $$b = - ax + y$$
| Points(x,y) | b = - ax + y | Line slope points (a,b) |
|---|---|---|
| A (3, 4) | b = - 3a + 4 | (1.33, 4) |
| B (0, - 4) | b = -4 | (0, 4) |
| C (1, 4) | b = - a + 4 | (4, 4) |
| D (6, 12) | b = -6a + 12 | (2, 12) |
| E (4, 1) | b = -4a + 1 | (0.25, 1) |
| F(1.5, 0) | b = - 1.5a + 2 | (1.33, 2) |
| G( - 2, 2) | b = 2a + 2 | ( - 1, 2) |
| H(- 1, - 3) | b = a – 3 | (3, - 3) |
| I( 3, - 2) | b = - 3a – 2 | ( - 2, - 0.667) |
Plotting line slope points, refer Graph 1
From the graph, it is clear that a maximum pf three-line pass through point
(2.667, - 4). i.e. a = 2.667, b = - 4
Putting a and b values in line equation,
$$y = ax +b \\ y = 2.667x - 4$$
i.e. x = 1.5 and y = - 4
Therefore, final plot can be plotted as,
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