Question: Determine the maximum weight 'w' that can be supported by two wires as shown in figure if the stress in each wire is not exceed to 120N/mm2.

0

Question: Determine the maximum weight 'w' that can be supported by two wires as shown in figure if the stress in each wire is not exceed to 120N/mm2.

0

0

Stresses in wire 1 and 2 is 120 N/mm^2. And area as A1=200 mm^2 and A2=250 mm^2 Now considering the stresses as c and σ2 in wire 1 and 2. Let forces be F1 and F2 in wire 1 and 2 respectively.

Now, Stress=Force/Area. Therefore, σ1=F1/A1 120=F1/200, F1=24,000 N=24KN & 120=F2/250,F2=30,000 N=30KN

For wire by Sine Rule; F1/sin(45)=W/sin(70) 24/sin(45)=W/sin(70) W=31.89 KN......(1)

F2/sin(65)=W/sin(70) 30/sin(65)=W/sin(70) W=31.10 KN......(2)

For Safe load, we consider minimum of (1) and (2). Therefore W=31.10 KN (answer)

Please log in to add an answer.

Site

Use of this site constitutes acceptance of our User
Agreement
and Privacy
Policy.