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Minimize the following expression using Quine McClusky Technique

$$F(A,B,C,D) = \sum m(1,3,7,9,10,11,13,15)$$

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Step 1. Grouping minterms according to number of 1s

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Step 2. Combining minterms in group of two

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Step 3. Combining minterms in group of four

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Interpreting from the table -

$F(A,B,C,D) = \bar B D + CD + AD$

Step 4. Prime Implicant table

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From the prime implicant table, $\bar B D, CD, AD$ are the Essential Prime Implicants.

Hence, the minimized expression will be - $F(A,B,C,D) = \bar B D + CD + AD$

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