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Numerical based on saponification value : An oil sample of saponification value 180 mg KOH
written 5.4 years ago by | • modified 2.2 years ago |
An oil sample of saponification value 180 mg KOH was saponified using 0.4 N alcoholic KOH solution. The blank titration reading was 50 ml of 0.4 N HCl solutions. Find the quantity of alcoholic KOH consumed by the oil per gm
Subject: Applied Chemistry 1
Topic: Lubricants Numericals
Difficulty: High
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