written 5.4 years ago by
teamques10
★ 64k
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modified 5.4 years ago
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Volume of practor mould = 945 c.c
∴ γbulk = (Mass of soil) + (Volume of soil) = 945 cc | gm/c.c
∴ γdry = {( γbulk)/(1+ω)}
w = % with content
= (G .γω)/(1+ ωG) (For saturate sample or for zero air void line)
Trail Number |
1 |
2 |
3 |
4 |
5 |
Mass of wet soil |
1673 |
1814 |
1928 |
1985 |
1947 |
γbulk X k (gm/c.c) |
1.77 |
1.97 |
2.04 |
2.1 |
2.06 |
ω = water content |
9.7 |
11.6 |
13.3 |
16.2 |
18.7 |
γdry = {( γbulk)/(1+ω)} |
1.613 |
1.72 |
1.8005 |
1.8076 |
1.735 |
Co–ordinate of zero air void line |
2.099 |
2.017 |
1.949 |
1.843 |
1.76 |
γ Co–ordinate of zero void line
γdry = (G .γω)/(1+ ωG)
= (2.7 X 9.81)/(1+(0.097)X (2.7)) = 2.099 { γ = 0.981, (G = 2.7)} (ω = 9.7%)
= (2.7 X 9.81)/(1+(0.116)X (2.7)) = 2.017 ( ω= 11.6%)
= (2.7 X 9.81)/(1+(0.133)X (2.7)) = 1.949 ( ω= 13.3%)
= (2.7 X 9.81)/(1+(0.162)X (2.7)) = 1.843 ( ω= 16.2%)
= (2.7 X 9.81)/(1+(0.187)X (2.7)) = 1.76 ( ω= 18.7%)
Calculated :
OMC = 16.2 %
MDD = 1.8076