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A rectangular duct section of 500mm x 350mm size carries 75 m^3/min of air having density of 1.15 kg/m^3 . Determine the equivalent diameter of a circular duct if-

1) The quantity of air carried in both the cases is same and

2) The velocity of air in both the cases is same

3) If f = 0.01 for sheet metal, find the pressure loss, per 100m length of duct.

Subject:- Refrigeration and Air Conditioning

Topic:- Duct Design, Controls & Applications

Difficulty:- Medium

1 Answer
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Given: a=500mm=0.5m

b=350mm=0.35m

Q=75/60=1.25 $m^3/sec$

$ρ=1.15 kg/m^3$

Calculating equivalent diameter of circular duct

1) The quantity of air carried in both the cases is same

D=1.265$\frac{ [(a^3 b^3)}{(a+b)]}^{(1/5)}$ D=0.46 m=459.23 mm

2) The velocity of air in both the cases is same

D=$\frac{2ab}{(a+b)}$

D=0.4117 m=411.76 mm

Also, pressure loss $P_f=\frac{f.l.v ̅^2.ρ}{2m}$…(1)

Where $v ̅=\frac{Q}{A}=\frac{1.25}{(0.5×0.35)}=7.14 m/sec, f=0.01, l=100, ρ=1.15 kg/m^3$

Hydraulic mean depth, m =$\frac{(cross-section area of flow)}{(wetted perimeter)}$

=$\frac{(a×b)}{2(a+b)}$ (for a rectangular duct)

=0.1029

Substituting all values in equation (1) we get, $P_f=284.76 Pa$

Dividing by 9.81, $P_f=29.03 mm of W.C. {Since 1\frac{N}{m}^2 =\frac{1}{9.81} mm of W.C.}$

[Tip: In duct designing it is a general practice to write pressures in mm of W.C.]

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