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Calculate the percentage atom economy for the following reaction :
written 5.2 years ago by | modified 4.1 years ago by |
$CH_3 NH_2 + CO Cl_2 → CH_3 N=C=O + 2HCl$
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written 5.2 years ago by | modified 4.1 years ago by |
$CH_3 NH_2 + CO Cl_2 → CH_3 N=C=O + 2HCl$
written 5.1 years ago by |
Molecular weight of $CH_3NH_2$ = 31
Molecular weight of $COCl_2$ = 98
Molecular weight of $CH_3N=C=O$ = 57
% Atom economy = Molecular weight of desired product/ Sum of the molecular weight of desired product $\times$ 100
= 57/31 +98 $\times$ 100
= 44.18%