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Prove that 50dB+50dB is not equal to 100dB.
1 Answer
written 5.2 years ago by |
50decibel= 20log10(Prms/20)
(Prms/20)= antilog(50/20)
Prms= 20∗316.2277
Prms= 6324.55
Here, ((Prms is Root mean square pressure)
Therefore, 50dB+50dBinr.m.s. = sqrt(6324)2+(6324.55)2
= 8944.26microPascal
Resultant sound pressure level= 20log10(Prms/20)dB
= 20log10(8944.26/20)dB
= 53 deciBels (dB)