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Design laterally unsupported beam ss over a span 2m i tcarry a udl 56kN/m
1 Answer
written 5.2 years ago by |
Given
w=56kN/m
factored load =56$\times1.5=8^{4}$kN/m
length of span=2m
Required =design laterally unsupported beam
1) V=$\frac{wd}{2}=\frac{84\times 2}{2}$=84kN
m$=\frac{wl^{2}}{8}=\frac{8^{4}\times 2^{2}}{8}$=42kN.m
2) Trial section
Zpreq=$\frac{M}{fbd}$
Assume $\lambda$=100 $\frac{h}{tf}$=25mm
fcrb=291.4 Md
250 $ \ \ \ \ $ 152.3
291.4 $ \ \ $ fbd
300 $ \ \ \ \ \ $163.6
fbd=161.65 …