1
19kviews
A block set associative cache consist of 64 blocks divided in 4 block sets. The main memory contains 4096 blocks, each 128 words of 16 bit length.
  1. How many bits are there in main memory address?

  2. How many bits are there in cache memory address (tags, set and word fields)?

1 Answer
4
5.4kviews

Given,

Number of blocks in cache memory = 64

Number of blocks in each set of cache = 4

Main memory size = 4096 blocks = $ 2^{12} $

Block size = 128 words = $ 2^7 $ words

Bits in Main Memory Address

Size of main memory = 4096 …

Create a free account to keep reading this post.

and 3 others joined a min ago.

Please log in to add an answer.