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Find out natural frequency of given system.
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Dist of CG from surface = $(\frac{4r}{3\pi})$

ANSLOM

IT = $\sum$ of all moments

+$ I_o \theta = -mg sin \theta \times (\frac{4r}{3\pi})$

$sin \theta \approx \theta$

$\therefore$ $Io \theta = -mg \theta (\frac{4r}{3\pi})$

$I_o \theta + mg (\frac{4r}{3\pi}) \theta = 0$

$ \theta + mg (\frac{4r}{3\pi}) \theta = 0$ …

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