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written 5.0 years ago by |
Dist of CG from surface = $(\frac{4r}{3\pi})$
ANSLOM
IT = $\sum$ of all moments
+$ I_o \theta = -mg sin \theta \times (\frac{4r}{3\pi})$
$sin \theta \approx \theta$
$\therefore$ $Io \theta = -mg \theta (\frac{4r}{3\pi})$
$I_o \theta + mg (\frac{4r}{3\pi}) \theta = 0$
$ \theta + mg (\frac{4r}{3\pi}) \theta = 0$ …