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written 4.9 years ago by |
$M = 70 \ kg$
$m = 10 \ kg$
$N = ?$
$r = 200 \ mm$
$F = 20 \ N$
$sin \ \alpha = \frac{200}{300} = 0.667$
$\alpha = 41.8°$
$sin \ \beta = \frac{200 – 40}{300}$
$\beta = 32.23°$
$q = \frac{tan \ \beta}{tan \ \alpha} …