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written 4.9 years ago by |
Minimum speed $= 240 \ rpm = N_1 , r = 140 \ mm$
Mass of fly ball $= m = 5 \ kg/4 \ kg$
$\therefore$ mean speed = $\frac{N_1 + N_2}{2} = 20(N_2 – N_1)$
$= \frac{240 + N_2}{2} = 20(N_2 – 240)$
$\therefore$ $N_2 = 252.3076 \ …