written 4.7 years ago by | • modified 4.7 years ago |
Solution:
$0 \cdot 8 \leq\left|H\left(e^{j \omega}\right)\right| \leq 1 \quad 0 \leq \omega \leq 0 \cdot 2 \pi$
$\left|H\left(e^{j \omega)} | \leq 0.2 \quad 0.6 \pi \leq \omega \leq \pi\right.\right.$
Given:
$\delta p=0.8 \quad \omega_{p}=0.2 \pi$
$\delta_{S}=0.2 \quad \omega_{S}=0.6 \pi$
Step 1: Obtain analog specifications.
$\Omega p=\frac{2}{T} \tan \left(\frac{\omega P}{2}\right)$
$=\frac{2}{0.1} …
written 4.7 years ago by | • modified 4.7 years ago |
Step 3: Cutoff frequency $\Omega c$
$\Omega c=\frac{\Omega p}{\left[\frac{1}{\delta^2 p}-1\right]^{1 / 2 N}}$
$\Omega_{C}=\frac{6.4983}{\left[\frac{1}{0.8^{2}}-1\right]^{1 / 4}}$
$\Omega_{C}= \ 7.5035 \ rad/sec$
Step 4: Transfer Function H(S)
N is even.
$H(s)=\frac{\Omega_{p}^{N}}{\prod_{k=1}^{N / 2} s^{2}+\Omega_{e} b_{k}S+\Omega_{C}^{2}}$
$H(s)=\frac{(7.5035)^{2}}{\pi_{k = 1} \ s^{2}+7.5035 b_{R} S+(5.5035)^{2}}$
$=\frac{56.3025}{S^{2}+7.5035 b_{1} S+56.3025}$
$b_{1}=2 \sin \left[\left(\frac{2 k-1}{2 N}\right) \pi\right]$ …