0
444views
Obtain digital filter transfer function by applying impulse in variance transfer function.
1 Answer
written 4.7 years ago by | • modified 4.7 years ago |
ANS
$H(s)=\frac{5}{(S+5)(S+2)}$ if $T=0.1 s$
Solution: Given:
$H(s)=\frac{s}{(s+5)(s+2)}$
Step 1: Obtain h(t) By I.L.T.
By PFE.
$H(s)=\frac{A}{s+5}+\frac{B}{s+2}$
$A=\left.(s+5) H(s)\right|_{s=-5}$ $A=5 / 3$
$B=(S+2) H(S) | S=-2$ $B=-2 / 3$
$H(s)=\frac{513}{s+5}-\frac{213}{s+2}$
$\therefore\left[h(t)=\frac{5}{3} e^{-5 t} u(t)-\frac{2}{3} e^{-2 t} u(t)\right]$
Step 2: Replace t = nT
$h(n)=\frac{5}{3} e^{-5 n T} \cdot u(n)-\frac{2}{3} e^{2 …