Figure 1 show the circuit diagram of RC phase shift oscillator.

The frequency of oscillation $f_O$ is given by,

$$f_o = \frac{1}{2π\sqrt{6}RC} = \frac{0.065}{RC}……….(1)$$

Let C=0.01uF so equation (1) becomes,

$f_O$ = 5KHz……Given

$$R = \frac{0.065}{5 X 10^3 X 0.001 X 10^-6}$$

$$R = 1.3KΩ$$

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