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Find moment of inertia of angle ISA : 100 mm x 75 mm x 6 mm about the centroidal XX and YY axis.
1 Answer
written 4.7 years ago by |
Solution:
a1 = 6 x 100 = $600mm^{2}$
a2 = 69 x 6 = $414mm^{2}$
x1 = 6/2 = 3mm.
x2 = 6 + 69/2 = 40.50mm
y1 = 100/2 = 50 mm
y2 = 6/2 = 3mm
$\bar{x} = \frac{a1x1 + a2x2}{a1 + a2} = 18.31 mm from (1) …