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Find the power that can be transmitted by a shaft of 40 mm dia. rotating at 200 RPM, if maximum shear stress is not to exceed 85 MPa.
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written 4.7 years ago by
teamques10
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Given:
For solid circular shaft d = 40mm, N = 200 rpm , $q_{max} = 85 N/mm^{2}$
Solution:
For solid shaft, $I_{p}$ =$ \frac{\pi}{32} \times d^{4}$ = $\frac{\pi}{32} \times 40^{4}$ = $2.51 \times 10^{5} mm^{4}$
R = d/2 = 40/2 = 20 mm
Using the relation, $\frac{T}{I_{p}}$ = $\frac{q_{max}}{R}$
$\therefore …
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