Ask
Login
0
12kviews
Determine the diameter of a solid steel shaft which will transmit 90 kW at 160 rpm. Also find the length of the shaft if the twist must not exceed $1^{o}$ over the entire length.
written 4.7 years ago by gravatar for teamques10 teamques10 ★ 65k •   modified 4.7 years ago

The maximum shear stress is limited to 60 N/mm2. Take the value of modulus of rigidity = 8 × 104 N/mm2.
need-tagging
ADD COMMENT EDIT
1 Answer
2
2.7kviews
written 4.7 years ago by gravatar for teamques10 teamques10 ★ 65k •   modified 4.7 years ago

Given:

For Solid circular steel shaft-

p = 90 kW = $90 \times 10^{3} watts$,

N = 160 rpm , $q_{max} = 60 N/mm^{2}$,

$G = 8 \times 10^{4} N/mm^{2}$

$\theta = a^{o} = 1 \times \frac{\pi}{180} = 0.0175 rad$

Solution:

$P = \frac{2 \pi N T_{avg}}{60}$

$90 \times 10^{3} …

Create a free account to keep reading this post.

and 3 others joined a min ago.

ADD COMMENT EDIT
Please log in to add an answer.