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Calculate the output voltage for the given amplifier.

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The negative sum is obtained by setting $V_3$ = 0. As shown in Figure 1,

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$$V'_O = -\frac{R_F}{R_1}V_1 - \frac{R_F}{R_1}V_2$$ $$V'_O= -\frac{R_F}{R_1}(V_1 + V_2)$$ Given $R_F$ = 100K, $R_1$ = 10K, $V_1$ = 1.5V and $V_2$ = 3V $$V'_O = -\frac{100K}{10K}(1.5 + 3)$$ $$\boxed{V'_O = -45V}..........(1)$$

Now set $V1$ = …

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