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${ show \ that } (\mathrm{ AB})^{-1}=\mathrm{C}^{-1} \mathrm{~A}^{-1}$
written 2.1 years ago by | modified 2.1 years ago by |
$$\text {If}, \mathrm{A}=\left[\begin{array}{cc} 2 & 3\\ -1 & 0 \end{array}\right];\quad \mathrm{B}=\left[\begin{array}{cc} -1 & 2\\ 0 & 1 \end{array}\right] \text {show that }(\mathrm{AB})^{-1}=\mathrm{B}^{-1} \mathrm{~A}^{-1}$$
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