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A gasoline-powered engine produces a peak output of 10 hp. Express the given power P in the SI.
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Solution:

Approach:

As listed in equations for derived units in the Uses, hp refers to horsepower, Then the Conversions for power.

$ \begin{aligned}\\ &1 h p_1=0.7457 \mathrm{kw} . \\\\ &1 h p=\frac{550(\mathrm{ft} \cdot 1 \mathrm{~b})}{\mathrm{s}}\\ \end{aligned}\\ $

Solution:

Here kijo prefix in, $1000=10^3$

Applying the Conversion factor to the engine's …

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