A reflex klystron operates under following conditions: $V_0=625 \mathrm{~V}, \mathrm{~L}=1 \mathrm{~mm}, \mathrm{R}_{\text {sh }}=14 \mathrm{~K} \Omega$ and $\mathrm{f}=8 \mathrm{GHz}$. If the device is operating at the peak of $1 \frac{3}{4}$ mode, Calculate a) Repeller Voltage and b) Efficiency.

Solution:

Reflex klystron,

Given:

$$ \begin{aligned} & V_0=625 \mathrm{~V}, L=1 \mathrm{~mm} \quad R_{s h}=14 \mathrm{k} \Omega \\ & f=8 \mathrm{CH}_2 \end{aligned} $$

the device operating mode is $13 / 4$ Hence $\quad n=2$

calculation,

$$ \begin{aligned} & \text { a) Reseller voltage }\left(v_\gamma\right) \\ & \frac{v_0}{\left(v_r+v_0\right)^2}=\frac{e}{m} \frac{(2 n \pi-\pi / …