A rectangle beam $230mm \times 450mm$ (effective depth) is reinforced with a bar of $16$ mm diameter out of which two bars are bent at $45^{\circ}$.

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A rectangle beam $230mm \times 450mm$ (effective depth) is reinforced with a bar of $16$ mm diameter out of which two bars are bent at $45^{\circ}$.

written 7.9 years ago by

teamques10 ★ 65k

modified 23 months ago by

sagarkolekar ★ 11k

Determine the shear resistance of the bent up bars and additional shear reinforcement required if the ultimate shear force is $300kN.$ Design shear reinforcement. Adopt M20 and $F_{e415}$

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building materials and construction

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written 7.9 years ago by

teamques10 ★ 65k

• modified 7.9 years ago

$$b=230 mm $$ $ d=450mm \\ V_{uD}=300 KN\\ Ast_{support}=4\times \dfrac \pi4 \times 16^2=804mm^2 \\ Ast_{lentup}= 2\times \dfrac \pi4 \times 16^2=402mm^2\\ Z_{uv}=\dfrac {V_{UD}}{b\times d}=\dfrac {300\times 10^3}{230\times 450}=2.7N/mm^2 \lt 2.8 N/mm^2 \therefore safe\\ pt=\dfrac {100Ast}{b\times d}=\dfrac {100\times 804}{300\times 450}=0.77N/mm^2$

shear stress in concrete $(Z_{uc})$

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$$V_{uc}=Z_{uc}bd=0.564\times 230\times 450=58.37KN$$ $$V_{u\space min}=0.4bd=0.4\times 230\times 450=41.4 KN$$ …

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Bro esame sv minimum nahi nikala hai usaka formula hai sv min = (0.87fy×asv÷(0.4b))

7.5 years ago by teamques10 ★ 65k

Bro esame sv minimum nahi nikala hai usaka formula hai sv min = (0.87fy×asv÷(0.4b))

7.5 years ago by teamques10 ★ 65k

Bro esame sv minimum nahi nikala hai usaka formula hai sv min = (0.87fy×asv÷(0.4b))

7.5 years ago by teamques10 ★ 65k

Bro esame sv minimum nahi nikala hai usaka formula hai sv min = (0.87fy×asv÷(0.4b))

7.5 years ago by teamques10 ★ 65k

Bro esame sv minimum nahi nikala hai usaka formula hai sv min = (0.87fy×asv÷(0.4b))

7.5 years ago by teamques10 ★ 65k

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