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Prove that eigen values of Hermitian matrix are real
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written 7.9 years ago by
teamques10
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Let A be a given Hermitian matrix, then $A^\theta = A$
Let $\lambda$ be the characteristic root of the matrix A with corresponding characteristic vector X then $AX = \lambda X$ (1)
Taking transpose conjugate of both the sides of (1) we get
$$\therefore (AX)^\theta = (\lambda X)^\theta \\ \therefore …
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