and 2 others joined a min ago.
0
6.9kviews
A cylinder of weight 500 N is kept on awe inclined planes as shown in the figure. Determine the reactions at the contact points A and B.
1 Answer
0
1.1kviews
written 7.8 years ago by
teamques10
★ 65k
|
Let A and B be the points of contact and Let C be the centre.
At C, Reaction forces $R_B , R_A$ and weight W are under equilibrium
$\therefore \dfrac {R_A}{\sin (180-30)}=\dfrac {R_B}{\sin (180-50)} =\dfrac {500}{\sin (30+50)} \\ \therefore \dfrac {R_A}{\sin (150)} =\dfrac {R_B}{\sin (130)} =\dfrac {500}{\sin (80)} \\ \therefore …
ADD COMMENT
EDIT
Please log in to add an answer.