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## User: Juilee

Juilee550
Reputation:
550
Status:
Trusted
Location:
Dombivli
Last seen:
2 months, 1 week ago
Joined:
1 year, 4 months ago
Email:
j***********@gmail.com

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#### Posts by Juilee

<prev • 3,598 results • page 1 of 360 • next >
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... $$P = 38 kW$$ $d = 225 mm\\ N_1 = 1440\\ N_2 = 360\\ i = 4\\ c = 1m$ For P = 38 and d = 225 mm Select cross section (PSG 7.58) For c - 8 Top width W = 22 mm Nominal thickness T = 14 mm D = idn D = 4 x 225 x 0.98 (assuming slip less than 2 %) D = 882 mm $D \approx 890 mm$ Length of belt $L ... written 5 months ago by Juilee550 1 answer 129 views 1 answer ... A v-belt drive is used to transmit 38 kW power at 1440 r.p.m. from a three phase induction motor to a centrifugal pump, required to be operated at 360 r.p.m. The motor pulley pitch diameter is 225 mm and the groove angle is$38^0$. The central distance between the pulleys is 1 m. The coefficient of ... written 5 months ago by Juilee550 1 answer 100 views 1 answers ... [R] =$K_s = K_1.K_2 K_3 K_4 K_5\\ K_1 = 1.25\\ K_2 = 1\\ K_3 = 1\\ K_4 = 1\\ K_5 = 1.25K_s = 1.5625[P] = 7.8125 is P \times K_s$By Resheter equation$P \geq 1.8 \sqrt[3]{\frac{[M_t]}{\sigma_{brg}m.z_1}}z_1 = 27$for i = 2 (PSG 7.74)$z_2 = iz_1 = 54 \approx 55$connected i = 2.0 ... written 5 months ago by Juilee550 1 answer 100 views 1 answer ... A chain drive is to be used to transmit 5 kW power from an electric motor running at 1000 r.p.m to a machine running at 500 r.p.m The service conditions involve light shock. i) Select a standard roller chain. ii) Determine the pitch circle diameters of driving and driven sprockets. iii) Determine t ... written 5 months ago by Juilee550 1 answer 111 views 1 answers ... For fit$H_8C_8C_{avg} = 0.126mm\frac{L}{D} = 0.5\\ \frac{2h_0}{c} = \frac{2 \times 15 \ times 10^{-3}}{0.126}= 0.23809$By interpolation s = 0.1347$\mu \frac{P}{C} = 4.1817\\ \frac{4 q}{DCn'L} = 5.3033\\ \frac{q_s}{q} = 0.8465\\ \frac{3c' \triangle to}{P} = 17.1328$Sammer field no$s ...
written 5 months ago by Juilee550
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... The following data is given for $360^0$ hydrodynamic bearing: Journal diameter $\hspace{2cm}$: 110 mm Bearing length $\hspace{2.3cm}$ : 55 mm Journal speed $\hspace{2.5cm}$: 1400 r.p.m Minimum oil-film thickness $\hspace{0.6cm}$: 15 microns Viscosity of lubricant $\hspace{1.6cm}$: 30cP Specifi ...
written 5 months ago by Juilee550
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... Calculation of revolution for each phase $n_1 = 0.01 \times N = 17.5\\ n_2 = 0.03 \times N = 52.5\\ n_3 = 0.21 \times N = 367.5 \\ n_4 = 0.75 \times N = 1312.5$ Mean revolution $\sum n = n_1 + n_2 + n_3 + n_4 = 1750 rpm$ calculation of mean load from variable load \$F_{rn} = \sqrt[3]{Fr_1^3n_1 + ...
written 5 months ago by Juilee550
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... A single row deep-groove ball bearing No. 6403 is used to support the lay shaft of a four speed automobile gear box. It is subjected to the following loads: | Gear | Axial load (N) | Radial Load (N) | Time engaged | |------|----------------|-----------------|--------------| | 1 | 3250 ...
written 5 months ago by Juilee550
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... Worm and worm wheel is basically used for transmission of high gear ratios. The worm and worm wheel is a pair wheel the physical drives has high contact i.e the area during the drive is very high. High area of contact means there is high amount of friction created, high amount of friction means h ...
written 5 months ago by Juilee550
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... **Mumbai University > Mechanical Engineering > Sem 7 > Machine Design 2** **Marks:** 6M **Year:** Dec 2016 ...
written 5 months ago by Juilee550

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