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User: Sanket Shingote

gravatar for Sanket Shingote
Sanket Shingote ♦♦ 180
Reputation:
180
Status:
Trusted
Location:
Dombivli
Website:
http://www.kt280.com/
Twitter:
sanket1893
Last seen:
5 days, 18 hours ago
Joined:
1 year, 1 month ago
Email:
s***************@gmail.com

"Fighting till the end" nature makes me perfect team mate.

I am a Textile Technologist from Mumbai's renowned university ICT (Institute of Chemical Technology)

I am currently working with KT280 as an analyst. I have keen interest in branding startups and social media marketing.

I am passionately working on Community Growth on Ques10. Pleased to meet you!

 

Posts by Sanket Shingote

<prev • 162 results • page 1 of 17 • next >
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5 critical interview tips
... New-age employers are going all out to keep people engaged and happy in their work spaces. Here are five popular ways that companies are resorting to keep their employees happy. #1. Professional introduction Every interviewer asks for an introduction. A candidate should be prepared with the best ...
interview written 12 weeks ago by Sanket Shingote ♦♦ 180
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Answer: A: Find the expression of x in terms of $\xi$ when : 1) Third node R is taken at (6
... Quadratic element with nodes 3. $\hspace{1cm}x=\phi, x_1+\phi_2x_2+ \phi_3 x_3 $ where, $\phi,=\frac{1}{2}\xi(\xi-1), \phi_2=\frac{1}{2}\xi (\xi+1),\phi=(1-\xi)(1+\xi)$ ![enter image description here][1] $x=\frac{1}{2}\xi(\xi-1)x_1+\frac{1}{2}\xi(\xi+1)x_2+(1-\xi)( ...
written 3 months ago by Sanket Shingote ♦♦ 180
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Find the expression of x in terms of $\xi$ when : 1) Third node R is taken at (6.0)
... Coordinates of the nodes of finite element are given by P (4.0) and Q (5.0) Find the expression of x in terms of $\xi$ when : 1) Third node R is taken at (6.0) 2) Third node R is taken at (5.0) Comment on the result. **Mumbai University > Mechanical Engineering > Sem 6 > Finite Elemen ...
mumbai university finite element analysis written 3 months ago by Sanket Shingote ♦♦ 180
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Answer: A: Estimate the natural frequencies of axial vibration of the bar using both consi
... ![enter image description here][1] $L\rightarrow he \rightarrow $ length of element. $E \rightarrow$Modular of elasticity. $S\rightarrow $density of material $A \rightarrow$ cross sectional area . (i) Natural freoquencies $w_i$ using consistent mass matrix . The element matrix is given ...
written 3 months ago by Sanket Shingote ♦♦ 180
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Estimate the natural frequencies of axial vibration of the bar using both consistent and lumped mass matrices.
... Consider a uniform cross section bar of length L made up of a material whose Yong's modulus and density are given by E and $\rho$.Estimate the natural frequencies of axial vibration of the bar using both consistent and lumped mass matrices. ![enter image description here][1] **Mumbai University ...
mumbai university finite element analysis written 3 months ago by Sanket Shingote ♦♦ 180
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Answer: A: Determine the strains $e_x,e_y,e_z$ and corresponding element stresses.
... $\hspace{1cm} x_1= 10 mm\hspace{1cm} y_1= 10 mm\\ \hspace{1cm} x_2= 70 mm\hspace{1cm} y_2= 35 mm\\ \hspace{1cm} x_3= 75 mm\hspace{1cm} y_1= 25 mm$ $\beta_1=y_2-y_3 = 10\hspace{2.5cm} r_1= x_3-x_2=5\\ \beta_2=y_3-y_1 = 15\hspace{2.5cm} r_2= x_1-x_3=65\\ \beta_1=y_1-y_2 = 25\hspace{2.5cm} r_3= x_2- ...
written 3 months ago by Sanket Shingote ♦♦ 180
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Determine the strains $e_x,e_y,e_z$ and corresponding element stresses.
... A CST element has nodal coordinates (10,10) , (70, 35) for nodes 1,2 and 3 respectively. The element is 2 mm thick and is of material with properties E=70 GPA. Poisson's ratio os 0.3. After applying the load to the element the nodal deformation were found to be $u_1=0.01mm, \ \ v_1=-0.04mm \ \ u_2= ...
mumbai university finite element analysis written 3 months ago by Sanket Shingote ♦♦ 180
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Answer: A: Find nodal displacement and element stress for the bar as shown in figure using
... ![enter image description here][1] $k_1 =\frac{AE}{L}$ $\begin{bmatrix} \ 1 & -1 \\ \ -1 & 1 \\ \end{bmatrix}= \frac{200\times200\times10^3}{300}$ $\begin{bmatrix} \ 1 & -1 \\ \ -1 & 1 \\ \end{bmatrix}=10^3$ $\begin{bmatrix} \ 166.67 & -166.67 \\ \ -166.67 & 166.67 \\ \end{ ...
written 3 months ago by Sanket Shingote ♦♦ 180
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Find nodal displacement and element stress for the bar as shown in figure using FEM. Take $E=200GP_a$
... ![enter image description here][1] **Mumbai University > Mechanical Engineering > Sem 6 > Finite Element Analysis** **Marks:** 10M **Year:** Dac 2016 [1]: http://i.imgur.com/QJkZ1Jm.png ...
mumbai university finite element analysis written 3 months ago by Sanket Shingote ♦♦ 180
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Answer: A: Analyze the truss completely for displacement, stress and strain as shown in fig
... ![enter image description here][1] $\hspace{1cm}E=200 GPa$ $\hspace{1.3cm}= 200\times 10^3 \frac{n}{mw^2}$ | Ele No. | Nodes | L | A | 0 | c | s | cs | $c^2$ | $s^2$ | $\frac{AE}{L}:$ | |----------|-------|-------|-----|------|--------|-------|------|-----|-----|---- ...
written 3 months ago by Sanket Shingote ♦♦ 180

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