User: Gyanendra pal

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Posts by Gyanendra pal

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Answer: A: A cantilever beam of cross section $300mm\times600mm $ and span 3m is loaded wit
... ![enter image description here][1] Maximum B.M $= \frac{WL^2}{2}=\frac{12\times3^2}{2}=\underline{54\ kNm}$ $M=54\ kNm\\ \theta=35^\circ\\ b=300\ mm\\ d=600\ mm $ Location of N.A $ I_{XX}=I_{UU}=\frac{bd^3}{12}=\frac{300\times600^3}{12}=5.4\times10^9mm^4\\ I_{YY}=I_{VV}=\frac{db^3}{12}=\frac ...
written 9 months ago by Gyanendra pal10 • updated 8 months ago by Sanket Shingote ♦♦ 250
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A cantilever beam of cross section $300mm\times600mm $ and span 3m is loaded with UDP of 12 kN/m over its entire span. Find the maximum bending stresses induced in the cross sectin if the ...(contd.)
... **Question** (contd.) plane of loadingis inclined at $35^\circ$ with minor axis in clockwise direction. Also locate the neutral axis position. **Subject :** Structural Analysis 1 **Topic :** Unsymmetrical Bending **Difficulty :** Medium ...
sa1(74) written 9 months ago by Gyanendra pal10 • updated 9 months ago by saxena_archit150
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Answer: A: A beam of rectangular cross section $80\times120$ mm is subjected to a uniformly
... ![enter image description here][1] Maximum B.M = $\frac{WL^2}{8}=\frac{10\times6^2}{8}={45\ kN}$ $ \underline{M=45\times10^6\ Nmm}\\ \theta=30^\circ$ **Location of N.A** $I_{XX}=I_{UU}=\frac{bd^3}{12}=\frac{80\times120^3}{12}=11.52\times10^6\ mm^4\\ I_{YY}=I_{VV}=\frac{db^3}{12}=\frac{120\time ...
written 9 months ago by Gyanendra pal10 • updated 8 months ago by Sanket Shingote ♦♦ 250
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A beam of rectangular cross section $80\times120$ mm is subjected to a uniformly distributed load of 10 kN/m. The plane of loading makes an angle of $30^\circ$ with respect to y-axis.
... If the span of beam is 6m, locate the neutral axis and hence find the stresses at each corners of the beam. --- **Subject :** Structural Analysis 1 **Topic :** Unsymmetrical Bending **Difficulty :** HIgh ...
sa1(74) written 9 months ago by Gyanendra pal10 • updated 8 months ago by Sanket Shingote ♦♦ 250
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Answer: A: A beam of rectangular cls is subjected to B.M of 15 kNm in the plane as shown in
... Here, $\alpha=30^\circ$ $ \therefore \sin\alpha=0.5\ \ \ \ \ \ \ \cos\alpha=0.866$ The momentsof inertia of th section are $I_{XX}=\frac{100\times150^3}{12}=\underline{28125000\ mm^4}\\ I_{YY}=\frac{150\times100^3}{12}=\underline{12500000\ mm^4} $ ![enter image description here][1] $\tan\beta=\f ...
written 9 months ago by Gyanendra pal10 • updated 8 months ago by Sanket Shingote ♦♦ 250
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A beam of rectangular cls is subjected to B.M of 15 kNm in the plane as shown in figure. Find maximum stresses in the section
... **Subject :** Structural Analysis 1 **Topic :** Unsymmetrical Bending **Difficulty :** High ![enter image description here][1] [1]: https://i.imgur.com/81BfpmJ.jpg ...
sa1(74) written 9 months ago by Gyanendra pal10 • updated 9 months ago by saxena_archit150
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Answer: A: Explain unsymmetrical bending
... ![enter image description here][1] 1. When the plane of bending does not coincide or parallel to the plane containing the principal centroidal axis of cross section is called as unsymmetrical bending. It is also known as complex or biaxial bending. 2. In unsymmetrical bending, the direction of t ...
written 9 months ago by Gyanendra pal10 • updated 9 months ago by saxena_archit150
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Explain unsymmetrical bending
... **Subject :** Structural Analysis 1 **Topic :** Unsymmetrical Bending **Difficulty :** High ...
sa1(74) written 9 months ago by Gyanendra pal10 • updated 9 months ago by saxena_archit150
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Answer: A: Determine the shear centre as shown in the figure
... ![enter image description here][1] $ I=I_{XX_1}-I_{XX_2}=\left[ \frac{100\times400^3}{12}\right]-\left[ \frac{(100\times20)(400-2\times20)}{12}\right]\\ I=(533.33\times10^6)-(311.04\times10^6)\\ \underline{I=222.3\times10^6mm^4}$ **Distance of shear centre (e)** $e=\frac{h^2b^2t}{4I}=\frac{400^ ...
written 9 months ago by Gyanendra pal10 • updated 8 months ago by Sanket Shingote ♦♦ 250
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Determine the shear centre as shown in the figure
... **Subject :** Structural Analysis 1 **Topic :** Shear Centre **Difficulty :** High ![enter image description here][1] [1]: https://i.imgur.com/zY9KOP6.jpg ...
sa1(74) written 9 months ago by Gyanendra pal10 • updated 9 months ago by saxena_archit150

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