## User: sesha321

sesha321 •

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#### Academic profile

#### Posts by sesha321

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Answer:
A: Problem on Chimney.

... ![enter image description here][1]
[1]: https://i.imgur.com/HxZNtwv.png
moment of Inertia of the base section about a diameter is
$ I = {\pi\ times(D^4-d^4)\over 64 }={\pi\times(3^4-2^4) \over 64 }= {3.191 m^4 }$
area of the base is given b ...

written 7 days ago by
sesha321 •

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... we are given with the following data
for a hollow steel shaft
the internal diameter is 200 mm and external diameter is 300 mm
and we are given with the rigidity modulus of steel as $2.4\times G\ N\over mm^2$
now whatever to be found out is the dia and rigidity modulus of the solid shaft
The ...

written 8 days ago by
sesha321 •

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... For the given composite shaft
the diameter of the steel rod is 19 mm (d)
torque is T= $(520\times 10^3)$
the rigidity modulus of steel is given by $8\times 10^9 {N\over mm^2}$
rigidity modulus of brass tube is to be found out
outside dia of brass tube is 32
length if the composite bar is ...

written 8 days ago by
sesha321 •

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... given data :
power transmitted P = 550KW
Number of rotations N = 115rpm
i) Here what to be found out is the diameter of the solid shaft. This can be found by using torsion equation
$${T\over J}= {\tau\over R}$$
torque can be calculated by the formulae
...

written 9 days ago by
sesha321 •

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