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User: sesha321

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sesha3210
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Posts by sesha321

<prev • 4 results • page 1 of 1 • next >
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Answer: A: Problem on Chimney.
... ![enter image description here][1] [1]: https://i.imgur.com/HxZNtwv.png moment of Inertia of the base section about a diameter is $ I = {\pi\ times(D^4-d^4)\over 64 }={\pi\times(3^4-2^4) \over 64 }= {3.191 m^4 }$ area of the base is given b ...
written 7 days ago by sesha3210
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Answer: A: A hollow steel shaft 20 cm internal and 30 cm external diameter is to be replace
... we are given with the following data for a hollow steel shaft the internal diameter is 200 mm and external diameter is 300 mm and we are given with the rigidity modulus of steel as $2.4\times G\ N\over mm^2$ now whatever to be found out is the dia and rigidity modulus of the solid shaft The ...
written 8 days ago by sesha3210
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Answer: A: Problem on Torsion; Shaft in Parallel
... For the given composite shaft the diameter of the steel rod is 19 mm (d) torque is T= $(520\times 10^3)$ the rigidity modulus of steel is given by $8\times 10^9 {N\over mm^2}$ rigidity modulus of brass tube is to be found out outside dia of brass tube is 32 length if the composite bar is ...
written 8 days ago by sesha3210
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Answer: A: Problem on Torsion for finding diameter of solid shaft and internal and externa
... given data : power transmitted P = 550KW Number of rotations N = 115rpm i) Here what to be found out is the diameter of the solid shaft. This can be found by using torsion equation $${T\over J}= {\tau\over R}$$ torque can be calculated by the formulae ...
written 9 days ago by sesha3210

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