## User: tanya.tanyabarnwal Reputation:
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#### Posts by tanya.tanyabarnwal

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Answer: A: Chapter 3 .
... **Solution:** (i) p=10%=0.1 q=1-p=0.9 n=5 $P(X=Y)=^{n}C_{r}p^{r}q^{n-r}$ For at the most two are defective r=0, 1, 2 $P(X=0 \ or \ 1 \ or \ 2)=^{5}C_{0}(0.1)^{0}(0.9)^{5}+^{5}C_{1}(0.1)^{1}(0.9)^{4}+^{5}C_{2}(0.1)^{2}(0.9)^{3}$ $P(X=0 \ or \ 1 \ or \ 2)=0.59049+0.32805+0.0729=0.99144$ (ii) ...
written 5 weeks ago by tanya.tanyabarnwal0
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... $A=\begin{bmatrix} 1 & 2 & -2 \\ -1 & 3 & 0 \\ 0 & -2 & 1 \end{bmatrix}$ ...
written 5 weeks ago by tanya.tanyabarnwal0
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... Use the dual simplex method to save the following LPP: Minimize, $z=2x_{1}+x_{2}$ subject to, $3x_{1}+x_{2} \ge 3$ $4x_{1}+3x_{2} \ge 6$ $x_{1}+2x_{2} \le 3$ $x_{1}, \ x_{2} \ge 0$ ...
written 5 weeks ago by tanya.tanyabarnwal0
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... Justify if there is any relationship between sex and color for the following data: | Color | Male | Female | |:-----:|:----:|:------:| | Red | 10 | 40 | | White | 70 | 30 | | Green | 30 | 20 | ...
written 5 weeks ago by tanya.tanyabarnwal0
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... Check whether the following matrix is derogatory or non-derogatory. $A=\begin{bmatrix} 6 & -2 & 2 \\ -2 & 3 & -1 \\ 2 & -1 & 3 \end{bmatrix}$ ...
written 5 weeks ago by tanya.tanyabarnwal0
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... (i) If 10% of the rivets produced by a machine are defective, find the probability that out of 5 randomly chosen rivets at the most two will be defective. (ii) If x denotes the outcome, when a fair dice is tossed, find the M.G.F. of x and hence find the mean and variance of x. ...
written 5 weeks ago by tanya.tanyabarnwal0
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Answer: A: Chapter 1 .
... **Solution:** Consider, $\int_{0}^{2\pi}\cfrac{\cos{2 \theta}}{5+4 \cos {\theta}} d\theta$ Put $z=e^{j \theta}$ -----------(1) $dz=j e^{j \theta} d\theta$ $d\theta=\cfrac{dz}{jz}$ ---------------(2) $\cos {\theta} = \cfrac{e^{j \theta} + e^{-j \theta}}{2} =\cfrac{z+z^{-1}}{2}=\cfrac{z+\cfrac{1} ... written 5 weeks ago by tanya.tanyabarnwal0 1 answer 44 views 1 answer ... Using the residue theorem, Evaluate$\int_{0}^{2\pi}\cfrac{\cos{2 \theta}}{5+4 \cos {\theta}} d\theta$. ... written 5 weeks ago by tanya.tanyabarnwal0 1 answer 57 views 1 answers Answer: A: Chapter 4 . ... **Solution:**$\bar{X}=9.3, \ \mu=8.9, \ s=1.6, \ n=50$(i) Null Hypothesis$(H_{o}): \ \mu_{1}=\mu_{2}$Alternate Hypothesis$(H_{a}): \ \mu_{1} \ne \mu_{2}$(ii) Test statistic$Z=\cfrac{\bar{X}- \mu}{s/ \sqrt{n}}= \cfrac{9.3-8.9}{1.6 / \sqrt{50} }=1.7678\$ (iii) Level of significance at 5%, ...
written 5 weeks ago by tanya.tanyabarnwal0
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... An ambulance service claims that it takes on an average 8.9 minutes to reach the destination in emergency calls. To check this the licensing agency has then timed on 50 emergency calls, getting a mean of 9.3 minutes with a standard deviation of 1.6 minutes. Is this acceptable at 5% LOS? ...
written 5 weeks ago by tanya.tanyabarnwal0

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