## Renu Banswani Title:
Moderator
Status:
Trusted

Email:
r***********@gmail.com
Location:
kalyan

Last seen:
1 day, 3 hours ago
Joined:
2 months, 1 week ago

#### Academic profile None None None None

#### Posts by Renu Banswani

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... $\because$ $I_c = \frac{1}{2} Icsat$ $= \frac{1}{2} \times (8MA) = 4mA$ $I_cq = 4MA$ $V_cc = 28$ ![enter image description here] $\therefore$ $I_c = \frac{v_cc - V_c}{R_c}$ $4mA = \frac{28-18}{R_c}$ $\therefore$ $R_c = \frac{10}{4mA} = 2.5 K$ $R_c = 2.5 K$ Selecting $V_CEQ = \frac{1}{2} ... written 1 day ago by Renu Banswani10 1 answer 13 views 1 answer ...$I_cq = \frac{1}{2}I_csatI_csat = 8mA$Vc = 18 v and B = 110 Determine$R_c, R_t$and$R_B$![enter image description here] Solution: Drawing DC load line for above ckt ![enter image description here] : https://i.imgur.com/vrXaZgb.png : https://i.imgur.com/6dneSq1.pn ... written 1 day ago by Renu Banswani10 0 answers 9 views 0 answers ... The minimum sampling rate of "2w" samples per second for a signal x(t) having maximum frequency of "w"$H_2$is called as "Nyquist rate" The reciprocal of Nyquist rate i.e.$(\frac{1}{2w})$is called as the Nyquist internal. Nyquist rate = 2w$H_2$Nyquist interval -$\frac{1}{2w}$seconds. - ... written 1 day ago by Renu Banswani10 0 answers 10 views 0 answers ... - Multiplexing is the process of simultaneously transmitting two or more individual signals over a single communication channel. due to multiplexing it is possible to increase the number of communication channels so that more information can be transmitted. - The typical applications of multiplexin ... written 1 day ago by Renu Banswani10 0 answers 11 views 0 answers ... - The operation of FDM is based on sharing the available bandwidth of a communication channel among the signals to be transmitted, this means that many signals are transmitted simultaneously with each signal occupying a different carrier. - Generally, the FDM systems are used for multiplexing the a ... written 1 day ago by Renu Banswani10 0 answers 12 views 0 answers ... In colpitts oscillator CE amplifier is used as amplifying element and LC circuit has a feedback element. Since CE amplifier provides phase shift of 180 degree between input and output, therefore feedback tank circuit has to provide additional 180 degree phase shift to full-fill Barkhausen's criter ... written 1 day ago by Renu Banswani10 0 answers 11 views 0 answers ... If the emitter current of a transistor is 8MA and 1B is$(\frac{1}{100})$of 1c determine the levels of 1C and 1B. **Solution:** Source of leakage current in a transistor. In BJT, as temperature increases covalent bonds in semiconductor lattice breaks and minority charge carriers are generated. th ... written 1 day ago by Renu Banswani10 0 answers 6 views 0 answers ... Adaptive delta modulation is a delta modulation system where step size is automatically varied depending upon the input analog signal. Output of the transmitter is string of continuous 1's or 0's, this indicates that overload has occurred that means DAC has lost the track of analog signal, with ada ... written 1 day ago by Renu Banswani10 0 answers 6 views 0 answers ... Consider op-amp in differential mode. ![enter image description here]$V_0 \alpha (v_1 - v_2)V_o = Ad ($v_1 - v_2)$ -----(1) where Ad is differential mode gain consider op-amp in common mode. ![enter image description here] $\therefore$ $V_o = Acm,Vcm$ ------(") where Acm is common m ...
written 1 day ago by Renu Banswani10
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... Determine the output voltage for the circuit, if $V_2 = 5v$ and $V_2 = 3v$ ![enter image description here] **Solution:** Consider only $V_1$ is applied and $V_2$ is $V_1$ is grounded. ![enter image description here] To find $v_x$ ![enter image description here] \$= \frac{20k}{20k + 20 ...
written 2 days ago by Renu Banswani10

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Centurion 26 days ago, created 100 posts.
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