Let us take the null hypothesis that the two population have the same variance i.e.
$$H_0\ :\ {\sigma }^1_i=\ {\sigma }^2_i$$
$$H_0\ :\ {\sigma }^1_i\neq \ {\sigma }^2_i$$
Alternative Hypothesis :
$$\sum{A_i} =331$$
$$n_1=9$$
$$\sum{B_i} =236$$
$$n_2=7$$
$$\overline{A} = \sum{A_i}/n_1 = 37$$
$$\overline{B} = \sum{B_i}/n_2 = 37$$
$$S^2_1=\ \frac{\sum{{(A_i-\overline{A})}^2}}{n_1-1} = 1134/8 = 141.75$$
$$S^2_2=\ \frac{\sum{{(B_i-\overline{B})}^2}}{n_2-1} = 341.4/6 = 56.9$$
$$F = \frac{S^2_1}{S^2_2}=2.49$$
F at 5% level of significance is 3.68
F calculated is 2.49 which is less than critical value (3.68)
Hence, Null hypothesis is accepted.
$\mathrm{\therefore }$ Population have the same variance.