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Mumbai university > FE > SEM 2 > Applied Physics II

Marks: 5M

Year: Dec 2013

Given:

$λ = 6000 A^0 = 6 × 10^{-7}$

$(a + b) = \frac{1}{5000}cm = \frac{1}{5} × 10^{-7}m$

To find:

Highest Order $(m_{max})$

Solution:

$m_{max} = \frac{a + b}{λ}$

$m_{max} = \frac{10^{-5}}{5 × 6 × 10^{-7}}$

$m_{max} = 3.33$

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