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Mumbai university > FE > SEM 2 > Applied Physics II
Marks: 5M
Year: Dec 2013
Given:
$λ = 6000 A^0 = 6 × 10^{-7}$
$(a + b) = \frac{1}{5000}cm = \frac{1}{5} × 10^{-7}m$
To find:
Highest Order $(m_{max})$
Solution:
$m_{max} = \frac{a + b}{λ}$
$m_{max} = \frac{10^{-5}}{5 × 6 × 10^{-7}}$
$m_{max} = 3.33$
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