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Collar B moves up with constant velocity $V_B=2 m/s$ . Rod AB is pinned at B. Find out angular velocity of AB and velocity of A.

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Mumbai University > FE > Sem 1 > Engineering Mechanics

Marks : 06

Years : MAY 2013

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$IB=2420mm \\ IA=1860mm \\ V_A = \dfrac {IA}{IB}.V_B \\ = \dfrac {1860}{2420} ×2 \\ \therefore V_A=1.537 m/s \Rightarrow Ans$

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